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Complex Output

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Complex Output
What will be the output of the following program?
public class ICreated {
    int ab;
    public static void main(String[] args) {
        new ICreated().add(5).print().sub(7).
    ICreated add(int i) {
        ab += i;
        return this.sub(ab);
    ICreated sub(int i) {
        ab = -i;
        return this;
    ICreated multiply(int j) {
        ab *= j;
        return this.add(ab);
    ICreated print() {
        System.out.print(ab + "#");
        return this;

A. -5#-7#-45#-4#
B. -5#-7#18#-4#-20#
C. 5#-7#-39#-4#-40#
D. -5#-7#-45#-4#40#
E. Some other output
F. Compilation Error or Runtime Error
Topic: Java Multiple Methods In One Class

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User comments below. All of them might not be correct.


Posted by Aruna Dantu    2014-01-29 08:25:11

f because the printing statement is wrong

Posted by Aruna Dantu    2014-01-29 08:25:34


Posted by Kick Bhasha    2014-01-29 08:26:00

answer is d because  add(5) returns -5 and then print() prints -5# sub(-7).print=-7#  multiply(3)=-45 as ab=-7  sub(4)=-4  multiply(5)=40 as ab=4

Posted by Akash Kolariya    2014-01-29 08:37:45

Answer is 'C'
explanation: considering ab to be 0 initially for the first step of print 5 is added separated by# is followed by subtraction of 7 then 5*7+4(.sub) followed by -(.sub) that is -4# and then -40#

Posted by Jigar Mehta    2014-01-29 08:43:16

f because there is compilation error in system.out.print

Posted by Pranavi Prakash    2014-01-29 09:05:06

E because in add function ab +=I that means ab value will be 6 and in sub function ab value is -6 so the ans should start with -6 so ans is e

Posted by Lavanya Kategaru    2014-01-29 11:31:16

ans is F becz ab is nt initilized..

Posted by Uday Kumar    2014-01-29 12:51:56

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Posted by Merit Campus    2014-01-30 04:26:44

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