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Minimum and Maximum Digits in a Number
What will be the output of the following program?
`public class MinMaxDigitInNumber{    public static void main(String args[])     {        int number = 1235689012;        range(number);    }    private static void range(int number)     {        int value1 = 0;        int value2 = 0;        for (value1 = value2 = number % 10; number > 0; number = number / 10)         {            if (value1 > number % 10)             {                value1 = number % 10;            }            if (value2 < number % 10)             {                value2 = number % 10;            }        }        System.out.print("Value1 : " + value1 + "  Value2 : " + value2);    }}`

 A. Value1 : 8  Value2 : 9 B. Value1 : 1  Value2 : 2 C. Value1 : 0  Value2 : 9 D. Value1 : 9  Value2 : 0 E. Compilation Error or Runtime Error
Topic:

### User comments below.All of them might not be correct.

The minimum value in the number "1235689012" is 0 so this is assigned to value1 and the maximum number is 9 so this is assigned to value2.

Posted by Amar Kumar Biradar    2014-02-10 09:21:16

Ans:D values1:9 it checks greatest no among all the digits value2:0 it checks the least no among all the digits

Posted by Indrasena Reddy    2014-02-10 09:23:07

answer is c,for loop is executed 3 times.after first 2 iterations if block of value1 is executed then  value1 =0.In third iteration if block of value2 is executed then value2=9.The final output is value1 : 0 value2 : 9

Posted by Praveen Kumar    2014-02-10 09:25:34

ans e: integer cant hold such a big value.

Posted by Neelima Nadikuda    2014-02-10 09:42:01

Ans:D ,Compilation error because 12345689012 is greater than "int" range.

Posted by Harish Kumar G    2014-02-10 09:44:33

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Posted by Merit Campus    2014-02-11 03:42:22

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Posted by Amar Kumar Biradar    2014-02-11 04:23:45