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Phone Rings
What will be the output of the following program?
`public class PhoneRings {    public static void main(String[] args) {        System.out.print(call(53) + " " + call(25));    }    public static int call(int number) {        System.out.print(number + ":");        if (number % 7 == 0) {            return 77;        }        if (number % 6 == 0) {            return 66;        }        return call(number - 1);    }}`

 A. 53:52:51:50:49:25:24:77 66 B. 53:52:51:50:49:77 25:24:66 C. Some other output or Compilation Error D. Throws StackOverflowError
Topic:

### User comments below.All of them might not be correct.

ans is (a) part...

Posted by Anuj Batham    2015-03-12 14:10:18

call(53) is executed first
Prints 53 and checks for if conditions which checks if number is divisible by 7 or 6, if true returns 77 or 66.Else call the method recursively by subtracting the number by 1.
This flow repeats until the number is 49 which is divisible by 7 and therefore it returns 77 after printing 53:52:51:50:49:
call(53) in System.out.print prints 53:52:51:50:49:77
Similarly call(25) prints 25:24:66
So the final output is 53:52:51:50:49:77 25:24:66

Posted by Shashanka Mogaliraju    2015-03-12 14:54:59

ANS is B

Here the concept of recursion is used.

--call() method is defined in which we check the divisibility of number by 7 and 6 and return 77 and 66 respectively.

--First,53 is passed to call () the method as it is not divisible by 7 and 6 so again call method is called by subtracting 1 from number I.e. 52 and it continues till it is divisible by 7 or 6.

So,
53:52:51:50:49:77 as 49 is divisible by 7 so 77 is returned.

--Again,call() method is called by passing 25.

Again it is neither divisible by 7 or 6 so again call() method is called by subtracting 1 from number.

So,
25:24:66 as 24 is divisible by 6 so 66 is returned.

OUTPUT:
53:52:51:50:49:77 25:24:66

Posted by Mânïshå Mùlchåndânï    2015-03-12 17:32:23

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Posted by Merit Campus    2015-03-13 01:43:27