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Sixes More Sixes and Dhoni2963

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Sixes More Sixes and Dhoni2963
What will be the output of the following program?
interface SixesMachine {
    void hitSixes();

public abstract class DhoniInTheMaking implements SixesMachine {
    public String numberOfSixes() {
        return "6 0 6 3 6 6 6 6";
    public void printRunsTrail(String runsAndRuns) {

class Dhoni extends DhoniInTheMaking {
    public static void main(String args[]) {
        DhoniInTheMaking outputClass = new Dhoni();
    public void hitSixes() {
        numberOfSixes().substring(5, 12);
        printRunsTrail(numberOfSixes().substring(4, 7));

A. 6 0 6 3 6 6 6 6
B. 6 3
C. 6 6
D. Compilation Error or Runtime Error
Topic: Difference Between Interfaces And Abstract Classes

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User comments below. All of them might not be correct.

Ans is we have the concept of abstract classes and interfaces..
abstract class is an class which contains the abstract methods and normal methods..
void one();--->abstract method
void one(){}--> normal method..
abstract methods will use full to act like a place holders in the parent class..
we cant create the instance for the abstract class but we can create reference for it...

if an class has only abstract methods than we can write it as interface...interfaces dont have normal methods...

here we have interface SixesMachine as interface with hitSixes() as abstract method
DhoniInMaking class implementing the these interfaced but we did not override the hitSixes() thats y we made this class as abstract..
classs Dhoni extending the DhoniInTheMaking class and this class overriding the hitSixes() main() we create reference for DhoniInTheMaking instance for the Dhoni and calling the hitSixes() so method in Dhoni class get executed and these we are sending the substring of 4,7 which is 6,3 so we are printing this string in printTrail()

Posted by Uday Kumar    2014-12-16 09:43:05

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Posted by Merit Campus    2014-12-17 06:55:39

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