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Strings replacement

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Strings replacement
What will be the output of the following program?
class StringBufferTest
    public static void main(String[] args)
        String s = "Infinity2K13";
        StringBuffer sb = new StringBuffer(s);
        for (int i = 0; i < s.length(); i++)
            char current = s.charAt(i);
            s.replace(current, Character.toUpperCase(current));
        sb.replace(9, 10, " 20");
        System.out.println(s.split('2')[0] + sb.substring(9));

A. Infinity 2013
D. Infinity2K13
E. Compilation Error
Topic: Java Character Class

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User comments below. All of them might not be correct.

Ans E beacase it requires one public class in main file

Posted by Manasa Jyothi Sree    2014-03-21 14:59:38

Ans is E because split method take string delimiter as its argument

Posted by Naga Sinst    2014-03-21 15:04:56

E. Compilation error occurs. The split method is supplied with an argument of  char type for which the method is not defined. The defined split() method expects a string variable as parameter.

Posted by Nikhil Sulibhavi    2014-03-21 15:11:37

E. in s.replace all the character in are replaced to uppercase and sb replaces 9 char to 20 and  split function must have string parameter but given as char it cannot match predefined function it gives compilation error

Posted by Navya Golla    2014-03-21 15:23:35

ans is E because there is no suitable method for split(char)  and the length actual and formal argument lists are various lengths

Posted by Adithya Aleti    2014-03-21 15:42:12

Congratulations Nikhil Sulibhavi. You are this dose winner. We will send you the link using which you can claim your recharge.

Posted by Merit Campus    2014-03-24 04:57:30

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