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Test on if
What will be the output of the following program?
public class AllTheBest {
    public static void main(String[] str) {
        boolean result;
        int ary[] = {2, 4, 8};
        result = groupSum(0, ary, 10);
        System.out.print(result + ", ");
        result = groupSum(0, ary, 9);
        System.out.print(result + ", ");
        result = groupSum(0, ary, 14);
    public static boolean groupSum(int start, int[] nums, int target) {
        if (start >= nums.length)
            return (target == 0);
        if (groupSum(start + 1, nums, target - nums[start]))
            return true;
        if (groupSum(start + 1, nums, target))
            return true;
        return false;

A. true, false, false
B. true, false, true
C. true, true, true
D. false, false, false
E. Compilation Error or Runtime Error
Topic: Learn Arrays And Loops

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User comments below. All of them might not be correct.


Posted by Goutham Singarapu    2015-02-03 04:01:51

Ans is B

Posted by Gopinath Manchikanti    2015-02-03 05:59:38


Here Recursion is used till the base condition is satisfied.

--true,true,false will be the output.

Posted by Mânïshå Mùlchåndânï    2015-02-03 18:59:23

ans b. initially we have 1d array assigned with 3 elements, so length of the array is 3.Boolean result assigned with one function which pass 3 parameters 0 ,array and 10 .here this function called recursively upto target reached 0, here initially 0 +1,arr,10-2=8,t hn 1+1,arr ,8-arr[1]=8-4=4.,nw we have groupsum (2+1,arr,4-8),so target value not reached 0, tryin nxt if condition returns true.thn 2 nd function has 0 ,arr,9 parameters, here also function recursively called but target not reached to 0.bcz in array we have even numbers. so result is false,3 rd function here 2 nd if condition returns true,1st pass start 1,target 12.2nd pass Start 2 target 8,3rd pass start 3 target start>=array lenth,target also 0 so returns true.

Posted by Maheshwari Natarajan    2015-02-03 19:39:34

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