Calculate sum of numbers using while and break

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Calculate sum of numbers using while and break

What will be the output of the following program?

class WhileExample
{
    public static void main(String s[])
    {
        int n = 0;
        int sum = 0;

        int count = 10;

        while( n <= 3 )
        {
            sum += (n * 2);

            if( count < 7 )
            {
                break;
            }
            count--;
            n++;

            if( n % 2 == 0 )
            {
                sum = sum * 3;
            }
        }

        System.out.println("sum = " + sum);
    }
}

A.	sum = 12
B.	sum = 48
C.	sum = 0
D.	sum = 14

Topic: Using Break In for Loop To Exit

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User comments below. All of them might not be correct.

Ans is B as the additions and multiplications related to sum variable with incrementing and decrementing of n and count will continue upto count is less than 7

Posted by Sai Avinash 2014-08-21 12:45:32

B. while loop                  if loop
1.n=0 ,so sum =0     -->    1.n=1,sum =0
2.n=1,sum =2         -->    2.n=2,sum =6
3.n=2,sum=10         -->    3.n=3,sum =10
4.n=3,sum =16        -->    4.n=4,sum=16*3=48

Posted by Prabhakar Reddy 2014-08-21 12:58:44

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Posted by Merit Campus 2014-08-22 05:13:47